Hi,
I have the question like this:
Is it possible to obtain a result depending on whether the variable belongs to the collection?

I mean the construction:

if x "belongs to" {1, 2, 4, 8} then x=0 else x=111
or even
if x "belongs to" {1, 2, 4, 8} else if x "belongs to {33, 45, 11) then x=99 else x=111

Thanks for an any response.
Jadalbert

Perhaps something like this?

elementsbelongs.sm (4,51 KiB) scaricato 1149 volta(e).

Wrote

I have the question like this:
Is it possible to obtain a result depending on whether the variable belongs to the collection?

This is too vague for real answer.
Yes, you can locate elements of an array that belongs as well to another array.
Please, visit an extensive example, posted next few minutes:
"Locate in array"
In simple one array is much simpler, please let know if desired.

Cheers.

Thank You both for help. I tested both example and it works. But I dont understand how can I add new line to method (function) cases()? If it is the function cases(), may be I'm wrong. I mean:
x := {1 if ...; 2 otherwise

Wrote

But I don't understand how can I add new line to method (function) cases()?

... like this
once you have if/otherwise [Cases], click right hand most place holder,
coma twice for one more if... again coma twice like before, DIY.
Cheers.

Wrote

Wrote

But I don't understand how can I add new line to method (function) cases()?

... like this
once you have if/otherwise [Cases], click right hand most place holder,
coma twice for one more if... again coma twice like before, DIY.
Cheers.

Ok, it works. But, I must use SEMICOLON twice. May be it is the same as coma (or comma) in real english. Im from Poland and my English is from school.
Anyway - thank You for help.
Jadalbert

Wrote

But, I must use SEMICOLON twice.

That's because the more correct answer about arguments or decimal separators would be "press your argument separator" or "press your decimal separtor", since you can customize them in Tools > Options