By same token of "Pipe Data", Colebrook Moody has been refactored.
Observe carefully the code to make the 'solve block' survive by
introducing it within a program structure. In this implicit solve,
the block needs an [one] initial value. Same code structure as
it was discovered in Mathcad 8/11 [undocumented].
A splendid piece of Engineering work for publishing and documenting
the project, tracable for the client's archive.

Jean




Inst_Colebrook MOODY.sm (16,74 KiB) descargado 1538 vez(es).

Inst_Colebrook Pipe Data.sm (24,35 KiB) descargado 1494 vez(es).

kW/hr is non-existent (physically nonsensical) unit of power. Power is measured in kW, and work is measured in kW*hr.

Wrote

kW/hr is non-existent (physically nonsensical) unit of power

Interesting: that's what alll Canadians we pay for 'kWh' consummed.
Billing may vary from Provinces to Provinces
Here is my billing for february 2016
"690 Kwh @ $ 0.0965/kWh"
My kW/hr is user to conform Q[T/hr] to deconfuse unit user confused.

Jean

... typos, updated, on-fly calculator added.

JeanInst_Colebrook Pipe Data.sm (60,85 KiB) descargado 1472 vez(es).

Wrote

Interesting: that's what alll Canadians we pay for 'kWh' consummed.
Billing may vary from Provinces to Provinces
Here is my billing for february 2016
"690 Kwh @ $ 0.0965/kWh"
My kW/hr is user to conform Q[T/hr] to deconfuse unit user confused.

Yes. kWh = kW*hr. This is unit of energy. Energy is integral of power by time, i.e. mean power multiplied by time. Power is measuted in kiloWatts, time in hours.

Wrote

Yes. kWh = kW*hr. This is unit of energy. Energy is integral of power by time, i.e. mean power multiplied by time. Power is measuted in kiloWatts, time in hours.

What you say is right, but not for design Engineer.
The Engineer wants to know the "POWER RATING" of the
motor to push Q[T/hr] via the pump it activates.
That's what the "Pipe Data" answers for those in that stuff.
Just introduce the 'r' efficiency factor from the supplier
of the 'MotorPump'.