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trouble with solve - Messages
#1 Posted: 6/10/2010 7:09:29 PM
I desire to solve this:
c:12-1,23*(1+x/2)
solve(c;x)=17,512195
I get the value of x, but if I write
c:12-1,23*(1+x/3)
solve(c;x)=
I get the message "no real roots" (in this case the value of x is 26,268292)
Someone can help me to understand why?
Stefano
c:12-1,23*(1+x/2)
solve(c;x)=17,512195
I get the value of x, but if I write
c:12-1,23*(1+x/3)
solve(c;x)=
I get the message "no real roots" (in this case the value of x is 26,268292)
Someone can help me to understand why?
Stefano
#2 Posted: 6/10/2010 9:09:22 PM
Stefano,
Try using the solve function with 4 arguments, where the third and fourth arguments are the lower and upper bounds respectively within which the root may be found. See screenshot below:

Graphing the function can help in choosing a suitable interval for the lower and upper bounds. Please see the following thread and wiki page for more info:
Solve not working
Solve function
BTW: An improved solve function would be a great plugin project for someone to work on.
Maybe someday.
Try using the solve function with 4 arguments, where the third and fourth arguments are the lower and upper bounds respectively within which the root may be found. See screenshot below:

Graphing the function can help in choosing a suitable interval for the lower and upper bounds. Please see the following thread and wiki page for more info:
Solve not working
Solve function
BTW: An improved solve function would be a great plugin project for someone to work on.

Will Massie
Mechanical Engineer
Oregon, USA
#3 Posted: 6/11/2010 4:55:20 PM
Thank you Maweilian,
before posting my question I read only this post http://en.smath.info/forum/default.aspx?g=posts&t=434, so I supposed that the need for an interval was only for non linear equation. I read carefully the posts you linked in your answer and now I understood the behaviour of solve function.
Thank you again.
Stefano
before posting my question I read only this post http://en.smath.info/forum/default.aspx?g=posts&t=434, so I supposed that the need for an interval was only for non linear equation. I read carefully the posts you linked in your answer and now I understood the behaviour of solve function.
Thank you again.
Stefano
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